2x^2+43x=472

Solution for 2x^2+43x=472 equation:

2x^2+43x=472

We move all terms to the left:

2x^2+43x-(472)=0

a = 2; b = 43; c = -472;
Δ = b2-4ac
Δ = 432-4·2·(-472)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-75}{2*2}=\frac{-118}{4}
=-29+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+75}{2*2}=\frac{32}{4}
=8
$